difsqr difference of squares


BinaryOperator


difsqr(a, b)

a difsqr: b

a.difsqr(b)


Return the value of  (a*a) - (b*b). This is more efficient than using

separate unit generators for each operation.


{ (FSinOsc.ar(800) difsqr: FSinOsc.ar(XLine.kr(200,500,5))) * 0.125 }.play;


same as :


(

{

var a, b;

a = FSinOsc.ar(800);

b = FSinOsc.ar(XLine.kr(200,500,5));

((a * a) - (b * b)) * 0.125

}.play)


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